View source for Ramanujan, S.

=Links=
*https://en.wikipedia.org/wiki/Srinivasa_Ramanujan

=Notes=
I tried calculating Ramanujan's series (as suggested by [[Crow 1999]]) to estimate 2/π in a spreadsheet. 

<math>1-5\left(\frac{1}{2}\right)^3+9\left(\frac{1\times3}{2\times4}\right)^3-13\left(\frac{1\times3\times5}{2\times4\times6}\right)^3+\cdots = \frac{2}{\pi}</math>

The products quickly became so large the spreadsheet returned an error after the first 151 terms. 

[[File:RamanujanSeries.png]]

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