Difference between revisions of "Probability of fixation"
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<math>u(p)=\frac{1-e^{4N_esp}}{1-e^{4N_es}}</math> | <math>u(p)=\frac{1-e^{4N_esp}}{1-e^{4N_es}}</math> | ||
| − | If we are considering the initial frequency of a single new mutation in the population | + | If we are considering the initial frequency of a single new mutation in the population ''p''=1/(2''N''<sub>''e''</sub>), |
| − | <math>u(p)_1=\frac{1-e^{4N_es\frac{1}{2N_e}}}{1-e^{4N_es}}=\frac{1-e^{2s}}{1-e^{4N_es}}</math> | + | <math>u(p)_1=\frac{1-e^{4N_es\frac{1}{2N_e}}}{1-e^{4N_es}}=\frac{1-e^{2s}}{1-e^{4N_es}}</math>. |
| + | |||
| + | If 4''N''<sub>''e''</sub>''s'' is large. | ||
| + | |||
| + | <math>u(p)_2\approx\frac{1-e^{2s}}{1}=1-e^{2s}</math>. | ||
Revision as of 06:40, 16 September 2018
[math]u(p)=\frac{1-e^{4N_esp}}{1-e^{4N_es}}[/math]
If we are considering the initial frequency of a single new mutation in the population p=1/(2Ne),
[math]u(p)_1=\frac{1-e^{4N_es\frac{1}{2N_e}}}{1-e^{4N_es}}=\frac{1-e^{2s}}{1-e^{4N_es}}[/math].
If 4Nes is large.
[math]u(p)_2\approx\frac{1-e^{2s}}{1}=1-e^{2s}[/math].
