Difference between revisions of "Probability of fixation"
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<math>u(p)_1=\frac{1-e^{4N_es\frac{1}{2N_e}}}{1-e^{4N_es}}=\frac{1-e^{2s}}{1-e^{4N_es}}</math>. | <math>u(p)_1=\frac{1-e^{4N_es\frac{1}{2N_e}}}{1-e^{4N_es}}=\frac{1-e^{2s}}{1-e^{4N_es}}</math>. | ||
| − | If 4''N''<sub>''e''</sub>''s'' is large | + | If 4''N''<sub>''e''</sub>''s'' is large |
<math>u(p)_2\approx\frac{1-e^{2s}}{1}=1-e^{2s}</math>. | <math>u(p)_2\approx\frac{1-e^{2s}}{1}=1-e^{2s}</math>. | ||
Revision as of 06:40, 16 September 2018
[math]u(p)=\frac{1-e^{4N_esp}}{1-e^{4N_es}}[/math]
If we are considering the initial frequency of a single new mutation in the population p=1/(2Ne),
[math]u(p)_1=\frac{1-e^{4N_es\frac{1}{2N_e}}}{1-e^{4N_es}}=\frac{1-e^{2s}}{1-e^{4N_es}}[/math].
If 4Nes is large
[math]u(p)_2\approx\frac{1-e^{2s}}{1}=1-e^{2s}[/math].
