Difference between revisions of "Coalescence"
From Genetics Wiki
(→Sum of the Infinite Series) |
(→Sum of the Infinite Series) |
||
| Line 4: | Line 4: | ||
<math>4N\sum_{i=2}^\infty\frac{1}{i(i-1)}=4N\sum_{i=1}^\infty\frac{1}{i(i+1)}=4N\sum_{i=1}^\infty\frac{1}{i}-\frac{1}{i+1}</math> | <math>4N\sum_{i=2}^\infty\frac{1}{i(i-1)}=4N\sum_{i=1}^\infty\frac{1}{i(i+1)}=4N\sum_{i=1}^\infty\frac{1}{i}-\frac{1}{i+1}</math> | ||
| + | |||
| + | Why is | ||
| + | |||
| + | <math>\frac{1}{i(i+1)}=\frac{1}{i}-\frac{1}{i+1}</math>? | ||
Revision as of 01:48, 18 September 2018
Sum of the Infinite Series
[math]\sum_{i=2}^\infty\frac{2N}{\frac{i(i-1)}{2}}=\sum_{i=2}^\infty\frac{4N}{i(i-1)}=4N\sum_{i=2}^\infty\frac{1}{i(i-1)}[/math]
[math]4N\sum_{i=2}^\infty\frac{1}{i(i-1)}=4N\sum_{i=1}^\infty\frac{1}{i(i+1)}=4N\sum_{i=1}^\infty\frac{1}{i}-\frac{1}{i+1}[/math]
Why is
[math]\frac{1}{i(i+1)}=\frac{1}{i}-\frac{1}{i+1}[/math]?
