Ramanujan, S.

Links

https://en.wikipedia.org/wiki/Srinivasa_Ramanujan

Notes

I tried calculating Ramanujan's series (as suggested by Crow 1999) to estimate 2/π in a spreadsheet.

[math]1-5\left(\frac{1}{2}\right)^3+9\left(\frac{1\times3}{2\times4}\right)^3-13\left(\frac{1\times3\times5}{2\times4\times6}\right)^3+\cdots = \frac{2}{\pi}[/math]

The products quickly became so large the spreadsheet returned an error after the first 151 terms.