Difference between revisions of "Fluctuating Population Size and Genetic Drift"
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This simple example illustrated two population sizes with half of the time spent at each. More generally | This simple example illustrated two population sizes with half of the time spent at each. More generally | ||
| − | <math>N_e=\frac{1}{\sum\limits_{i}{\frac{t_i}{N_i}}}</math> | + | <math>N_e=\frac{1}{\sum\limits_{i}{\frac{t_i}{N_i}}}</math>, |
| + | |||
| + | where ''t<sub>i</sub>'' is the fraction of the total time spent at each corresponding size ''N<sub>i</sub>''. | ||
to be continued ... (mention upper limit in time to effects, human example). | to be continued ... (mention upper limit in time to effects, human example). | ||
Revision as of 18:59, 22 September 2018
In general the variance from a binomial process is [math]\sigma^2 = n p (1-p)[/math], where n is the number of trials and p is the probability of one of the two outcomes.
The variance for the sampling of two alleles each generation is [math]2N p (1-p)[/math], where N is the diploid population size and p is the allele frequency.
We like to work with allele frequencies rather than allele counts in a population. The variation is scaled by 2N so the underlying standard deviation is a fraction between zero and one.
[math]\frac{\sigma}{2N} = \frac{\sqrt{2N p (1-p)}}{2N}[/math]
[math]\sigma^2 = \left(\frac{\sqrt{2N p (1-p)}}{2N}\right)^2 = \frac{2N p (1-p)}{4N^2} = \frac{p (1-p)}{2N}[/math]
Imagine the population fluctuating between two sizes, N1 and N2, so that it spends half of its time at N1 and half at N2. There is an effective population size, Ne, of constant size that has the same average variance in allele frequency change each generation as the fluctuating population.
[math]\frac{p(1-p)}{2N_e}=\frac{1}{2}\times\frac{p(1-p)}{2N_1}+\frac{1}{2}\times\frac{p(1-p)}{2N_2}[/math]
We can cancel out a lot of components to get
[math]\frac{1}{N_e}=\frac{1}{2}\times\frac{1}{N_1}+\frac{1}{2}\times\frac{1}{N_2}[/math]
and solve for Ne.
[math]N_e=\frac{1}{\frac{1}{2}\times\frac{1}{N_1}+\frac{1}{2}\times\frac{1}{N_2}}[/math]
This is a harmonic mean, the inverse of the average of the inverses of the individual population sizes.
Of the three standard types of means (the arithmetic, geometric, and harmonic) the harmonic mean has the lowest average (when there is a difference between the numbers being averaged. What this means here is that small population sizes count more and have a larger effect on the average long term dynamics of genetic drift.
This simple example illustrated two population sizes with half of the time spent at each. More generally
[math]N_e=\frac{1}{\sum\limits_{i}{\frac{t_i}{N_i}}}[/math],
where ti is the fraction of the total time spent at each corresponding size Ni.
to be continued ... (mention upper limit in time to effects, human example).
