Difference between revisions of "Ramanujan, S."

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https://en.wikipedia.org/wiki/Srinivasa_Ramanujan
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=Links=
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*https://en.wikipedia.org/wiki/Srinivasa_Ramanujan
  
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=Notes=
 
I tried calculating Ramanujan's series (as suggested by [[Crow 1999]]) to estimate 2/π in a spreadsheet.  
 
I tried calculating Ramanujan's series (as suggested by [[Crow 1999]]) to estimate 2/π in a spreadsheet.  
  
<math>1-5\left(\frac{1}{2}\right)^3+9\left(\frac{1\times3}{2\times4}\right)^3-13\left(\frac{1\times3\times5}{2\times4\times6}\right)^3+\ldots = \frac{2}{\pi}</math>
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<math>1-5\left(\frac{1}{2}\right)^3+9\left(\frac{1\times3}{2\times4}\right)^3-13\left(\frac{1\times3\times5}{2\times4\times6}\right)^3+\cdots = \frac{2}{\pi}</math>
  
 
The products quickly became so large the spreadsheet returned an error after the first 151 terms.  
 
The products quickly became so large the spreadsheet returned an error after the first 151 terms.  
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[[File:RamanujanSeries.png]]
 
[[File:RamanujanSeries.png]]
  
[[Category:People]]
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=What Links Here=
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{{Special:WhatLinksHere/{{FULLPAGENAME}}}}
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[[Category:Person]]

Latest revision as of 17:03, 30 September 2018

Links

Notes

I tried calculating Ramanujan's series (as suggested by Crow 1999) to estimate 2/π in a spreadsheet.

[math]1-5\left(\frac{1}{2}\right)^3+9\left(\frac{1\times3}{2\times4}\right)^3-13\left(\frac{1\times3\times5}{2\times4\times6}\right)^3+\cdots = \frac{2}{\pi}[/math]

The products quickly became so large the spreadsheet returned an error after the first 151 terms.

RamanujanSeries.png

What Links Here